##### Calculus

Please confirm what is the ans for this

##### 1Comment
shivani
9 Oct 2017 02:51 pm

F(x) = $\int_{-2}^{2} |1-x^4|dx$
put x=-x
we get F(-x) = F(x), so ,its an even function
which can be written as 2 *$\int_{0}^{2} |1-x^4|dx$
=2[$\int_{0}^{1} (1-x^4)dx + \int_{1}^{2} -(1-x^4)dx$]
on solving , we get 12