S suni @missiongate2018 added a Question 9 Oct 2017 Calculus Please confirm what is the ans for this 1Comment thumbs up down up0 like shivani @shivani1234 9 Oct 2017 02:51 pm F(x) = \(\int_{-2}^{2} |1-x^4|dx\) put x=-x we get F(-x) = F(x), so ,its an even function which can be written as 2 *\(\int_{0}^{2} |1-x^4|dx\) =2[\(\int_{0}^{1} (1-x^4)dx + \int_{1}^{2} -(1-x^4)dx\)] on solving , we get 12 up0 like Log in or register to post comments

F(x) = \(\int_{-2}^{2} |1-x^4|dx\)

put x=-x

we get F(-x) = F(x), so ,its an even function

which can be written as 2 *\(\int_{0}^{2} |1-x^4|dx\)

=2[\(\int_{0}^{1} (1-x^4)dx + \int_{1}^{2} -(1-x^4)dx\)]

on solving , we get 12