Probability of occurence of different numbers on 6 tossings of a fair dice

Probability of occurence of different numbers on 6 tossings of a fair dice

1Comment
shivani @shivani1234
30 Jul 2017 11:03 am

P(E)=no. of favourable cases/ total sample space 
=n(E)/n(S)
here, we can think of favourable events like this ,
we have got 6 places to put 1
we have got 5 places to put 2....
we have got 1 place to put 6
so, n(E)=6*5*4*3*2*1
and n(S)=6*6*6*6*6*6
thus, P(E)=n(E)/n(S)
=0.0154